Mathematics Prove ∑nk=1k=12n(n+1)∑k=1nk=12n(n+1) with Mathematical Induction Sunday April 3rd, 2016 Kenji Tweet Now, prove the following equation with Mathematical Induction. sumnk=1k=frac12n(n+1)sumk=1nk=frac12n(n+1) Continue reading Prove ∑nk=1k=12n(n+1)∑k=1nk=12n(n+1) with Mathematical Induction → Readers who viewed this page, also viewed:Git: git pull for all branches, each of them is tracking the remoteSummation of knkn Lead the FormulaAuthor Profile Tweet