Category Archives: Mathematics

Proof: Irrational numbers aa , bb exist that make abab rational number


Irrational numbers ( a ) , ( b ) exist that make ( a^b ) rational.

Prove with law of excluded middle and without fixing what ( a ) and ( b ) are.

Proof

Supporse ( x = sqrt{2} ^ sqrt{2} ) .

Case: ( x ) is Rational

( sqrt{2} ) is irrational, so ( a = b = sqrt{2} ) make ( a^b ) rational. ( ( sqrt{2} ) が無理数であることの証明は 証明: ( sqrt{2} ) は無理数 をご覧ください。)

Case: ( x ) is Irrational

begin{eqnarray*} sqrt{2} & = & (sqrt{2}^sqrt{2})^sqrt{2} & = & sqrt{2}^{sqrt{2} cdot sqrt{2}} & = & sqrt{2}^2 & = & 2 end{eqnarray*}

Then, ( a = x = sqrt{2}^sqrt{2} ) and ( b = sqrt{2} ) are irrational and make ( a^b ) rational.

Above all, there are irrational numbers ( a ) and ( b ) that make ( a^b ) rational.


Summation of knkn Lead the Formula


How much is the summation from 1 to 100?

ガウスがこの計算を即座にやってのけたという話はあまりに有名で、整数を順次足す、等差数列を順次足す方法はご存じの方も多いと思います。

よく使われる説明の方法として、石を三角の形に置き、それと点対象な三角の形に石を置くというのがあります。

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Proof: Infinite Decimal of Rational Number is Recurring Decimal


I prove that infinite decimal of rational number is recurring decimal. It is decimal of rational number but is not finite decimal.

While the process of division may seem intuitive, I will provide a more concrete explanation as a formal proof.

Feeling

For example, when 89 is sequentially divided by 13, including decimal places, the remainders are as follows:

89÷13=6remainder is11110÷13=8remainder is660÷13=4remainder is880÷13=6remainder is220÷13=1remainder is770÷13=6remainder is550÷13=3remainder is11110÷13=8remainder is6

On the 7th division, the same remainder as in the 1st division appeared again. Since there are only 12 possible remainers when divided by 13, ranging from 1 to 12, if the division doesn’t result in a perfect quotient after 13 divisions, it becomes evident that at some point, the same remainder would recur, leading to a repeating decimal.

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