Tag Archives: Edge

Calculate Pentagons and Hexagons in a Soccer Ball


There are many pentagons and hexagons in a soccer ball. Now, let’s calculate them.

Euler’s formula

On polyhedron, the following equation is valid.

(vertex count) – (edge count) + (face count) = 2

The proof of Euler’s formula is written on Think about Euler’s Formula on Polyhedron.

Now, using this formula, calculate the number of pentagons and hexagons. ( I calculated faces, etc. without Euler’s Equation on Soccer Ball and Regular Polyhedron . )

Calculate

Define m as the number of pentagons, and n as one of hexagons.

On soccer ball, one vertex is common in 3 planes. So, the number of vertexes on a soccer ball is expressed as 5m+6n3, the number of edges is 5m+6n2, the number of faces is m+n .

According to Euler’s formula, the following equation is valid.

5m+6n35m+6n2+m+n=2

Now, calculate the above equation and get the value of m .

m=12.

On a soccer ball, one pentagon neighbors 5 hexagons, and one hexagons neighbors 3 pentagons. Then, ( n ) is calculated as the following.

n=5m3=5×123=20.

From the above, the number of hexagons is 10, and the number of pentagons is 20.

You can calculate them with Descartes theorem. I wrote it on Proof of Descartes Theorem.

Note

The shape of Fullerene, C60, is the same as soccer ball. Let’s check whether the number of vertexes is 60.

5m+6n3=5×12+6×203=60.

Reference

Euler’s formula is explained in the following book.